Class 10 Science English Medium

Chapter 12: Electricity

Topics: Electric current, unit of current, potential and potential difference, prevailing symbols of useful equipments in electrical circuits, ohm’s law, resistance, dependence of resistance on length and cross-sectional area, resistivity, combination of resistances.

2290

1. The charge on an electron is........

$1.6\times {10}^{19}C$

$3.6\times {10}^{-6}C$

$3.6\times {10}^6C$

$1.6\times {10}^{-19}C$

2287

2. Resistance of a conductor ...............

independent of length

decreases with length

increases with length

none of the above

2739

3. 2 coulomb charge passes through an electrical circuit in 0.5 second. Find the value of electric current in ampere.

1 ampere

4 ampere

1.5 ampere

10 ampere

2277

4. If the length of a conductor is reduced to half (without cutting), its resistivity becomes:

half

doubled

remains same

quadrupled (four times)

2269

5. Which of the following is SI unit of electric charge?

ampere

coulomb

volt

joule

2279

6. Three resistances of 10 $\mathit{\Omega}$, 5 $\mathit{\Omega}$ and 2 $\mathit{\Omega}$ respectively are connected in parallel. Net resistance will be.................

more than 10$\mathit{\Omega}$

between 10$\mathit{\Omega}$ and 5$\mathit{\Omega}$

between 5$\mathit{\Omega}$ and 2$\mathit{\Omega}$

less than 2$\mathit{\Omega}$

2267

7. The S.I. unit of electric current is:

ohm

ampere

coulomb

volt

2268

8. The S.I. unit of electric charge is:

ohm

ampere

coulomb

volt

2270

9. Which of the following instrument is used to measure the potential difference?

Ammeter

Voltmeter

both of the above

none of the above

2273

10. If the cross-sectional area of an aluminium wire is doubled and length remaining same, its resistivity will ......

remain same

doubled

halved

none of the above

2284

11. The length of a conductor is halved. Its conductance will be ..............

halved

unchanged

doubled

quadrupled

2278

12. SI unit of resistance is.......

ohm

coulomb

metre

centimetre

2736

13. Three conducting wires of $1 \Omega, 2 \Omega \& 3 \Omega$ are connected in series in an electrical circuit. What will be the equivalent resistance?

Less than $1 \mathrm{Ohm}$

Less than $3 \mathrm{Ohm}$

More than $1 \mathrm{Ohm}$

More than $3 \mathrm{Ohm}$

2275

14. An electric bulb is rated 220 V and 100W. When it is operated on 110 V, the power consumed will be:

100 W

75 W

50 W

25 W

2733

15. 2 ampere current flows in a conductor connected with a $5 \mathrm{~V}$ battery. Find the resistance of the conductor

$3 \Omega$

$2.5 \Omega$

$10 \Omega$

$2 \Omega$

Important Points : Electricity

Clas 10 Science MCQs of this chapter based on the following topic take a brief revision of the cahpter Electirc Current.

Electric Current:

Rate of flow of charge is called current. Its direction is always taken from positive to negative and it is measured in amperes.

Electric Resistance:

Restriction in the flow of charge is called resistance. It depends upon lenght, cross section area, temperature and the material.

Ohm's Law:

When physical states of aconductor are constant then the potential difference produced across the conductor is proportional to the current flowing through it. It is called Ohm's law.

V = IR

Where R is a constant and is known as resistance of conductor.

Measurement of Electric Current and Potential Difference:

Ammeter measures current in the circuit and is used in series in the circuit.
Voltmeter measures the potential difference across the conductor and is placed parallel to it in a circuit.

Specific Resistance:

Resistance of a conducting wire of 1 meter length and 1 square meter cross sectional area is called specific resistance of the material of the wire. Its unit is ohm $\Omega m$ i.e. ohm-metre. It does not depend on length or cross-sectional area of the wire but depends on the material of the wire.

Equivalent resistance in series combination

$$ \mathrm{R}=\mathrm{R}_{1}+\mathrm{R}_{2}+\mathrm{R}_{3} \ldots \ldots $$

Equivalent resistance in parallel combination

$$ \frac{1}{\mathrm{R}}=\frac{1}{\mathrm{R}_{1}}+\frac{1}{\mathrm{R}_{2}}+\frac{1}{\mathrm{R}_{3}}+\ldots . . $$

A pure resistor is connected to an electric source. The energy given to the pure resistor by electric source $(\mathrm{W}=\mathrm{VIt})$ fully transforms into heat energy.